Base | Representation |
---|---|
bin | 111101001001000011… |
… | …1011010000001011011 |
3 | 110112220112221010201110 |
4 | 1322102013122001123 |
5 | 4122400402342021 |
6 | 140152451551403 |
7 | 12325514163105 |
oct | 1722207320133 |
9 | 415815833643 |
10 | 131300434011 |
11 | 5075874348a |
12 | 215442bb563 |
13 | c4c6432206 |
14 | 64d80a0575 |
15 | 36370dc476 |
hex | 1e921da05b |
131300434011 has 16 divisors (see below), whose sum is σ = 175984243200. Its totient is φ = 87076167360.
The previous prime is 131300434009. The next prime is 131300434117. The reversal of 131300434011 is 110434003131.
It is not a de Polignac number, because 131300434011 - 21 = 131300434009 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131300834011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 374946 + ... + 634968.
It is an arithmetic number, because the mean of its divisors is an integer number (10999015200).
Almost surely, 2131300434011 is an apocalyptic number.
131300434011 is a deficient number, since it is larger than the sum of its proper divisors (44683809189).
131300434011 is a wasteful number, since it uses less digits than its factorization.
131300434011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 260906.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 131300434011 its reverse (110434003131), we get a palindrome (241734437142).
The spelling of 131300434011 in words is "one hundred thirty-one billion, three hundred million, four hundred thirty-four thousand, eleven".
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