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1313011201003 = 2774740112639
BaseRepresentation
bin10011000110110101100…
…100001111001111101011
311122112010000012221120121
4103012311210033033223
5133003021331413003
62443104454504111
7163601433030115
oct23066544171753
94575100187517
101313011201003
11466932658077
12192578965037
1396a7c8bb548
144779b5cc3b5
152424b33acbd
hex131b590f3eb

1313011201003 has 4 divisors (see below), whose sum is σ = 1317751313920. Its totient is φ = 1308271088088.

The previous prime is 1313011200979. The next prime is 1313011201009. The reversal of 1313011201003 is 3001021103131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313011201003 - 213 = 1313011192811 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1313011201009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2370056043 + ... + 2370056596.

It is an arithmetic number, because the mean of its divisors is an integer number (329437828480).

Almost surely, 21313011201003 is an apocalyptic number.

1313011201003 is a deficient number, since it is larger than the sum of its proper divisors (4740112917).

1313011201003 is an equidigital number, since it uses as much as digits as its factorization.

1313011201003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4740112916.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1313011201003 its reverse (3001021103131), we get a palindrome (4314032304134).

The spelling of 1313011201003 in words is "one trillion, three hundred thirteen billion, eleven million, two hundred one thousand, three".

Divisors: 1 277 4740112639 1313011201003