Base | Representation |
---|---|
bin | 11101110110101011101101… |
… | …111000000011101111110011 |
3 | 122012220021012021121101000011 |
4 | 131312223231320003233303 |
5 | 114202214214112244243 |
6 | 1143130524520035351 |
7 | 36441123451650316 |
oct | 3566535570035763 |
9 | 565807167541004 |
10 | 131301141134323 |
11 | 3892255717a536 |
12 | 1288705a602b57 |
13 | 583584bc03224 |
14 | 245d01b11297d |
15 | 102a69d77c89d |
hex | 776aede03bf3 |
131301141134323 has 4 divisors (see below), whose sum is σ = 131824253250648. Its totient is φ = 130778029018000.
The previous prime is 131301141134279. The next prime is 131301141134327. The reversal of 131301141134323 is 323431141103131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131301141134323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131301141134327) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261556057786 + ... + 261556058287.
It is an arithmetic number, because the mean of its divisors is an integer number (32956063312662).
Almost surely, 2131301141134323 is an apocalyptic number.
131301141134323 is a deficient number, since it is larger than the sum of its proper divisors (523112116325).
131301141134323 is an equidigital number, since it uses as much as digits as its factorization.
131301141134323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 523112116324.
The product of its (nonzero) digits is 7776, while the sum is 31.
Adding to 131301141134323 its reverse (323431141103131), we get a palindrome (454732282237454).
The spelling of 131301141134323 in words is "one hundred thirty-one trillion, three hundred one billion, one hundred forty-one million, one hundred thirty-four thousand, three hundred twenty-three".
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