Base | Representation |
---|---|
bin | 11101110110101011110010… |
… | …000010100101100101001011 |
3 | 122012220021101011002002002202 |
4 | 131312223302002211211023 |
5 | 114202214340004100321 |
6 | 1143130535453350415 |
7 | 36441125260556564 |
oct | 3566536202454513 |
9 | 565807334062082 |
10 | 131301211003211 |
11 | 38922592661017 |
12 | 12887079a9840b |
13 | 5835860527172 |
14 | 245d0264dd16b |
15 | 102a6a497e70b |
hex | 776af20a594b |
131301211003211 has 4 divisors (see below), whose sum is σ = 131309556611712. Its totient is φ = 131292865394712.
The previous prime is 131301211003189. The next prime is 131301211003229. The reversal of 131301211003211 is 112300112103131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131301211003211 - 218 = 131301210741067 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131301211002211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4172780651 + ... + 4172812116.
It is an arithmetic number, because the mean of its divisors is an integer number (32827389152928).
Almost surely, 2131301211003211 is an apocalyptic number.
131301211003211 is a deficient number, since it is larger than the sum of its proper divisors (8345608501).
131301211003211 is an equidigital number, since it uses as much as digits as its factorization.
131301211003211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8345608500.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 131301211003211 its reverse (112300112103131), we get a palindrome (243601323106342).
The spelling of 131301211003211 in words is "one hundred thirty-one trillion, three hundred one billion, two hundred eleven million, three thousand, two hundred eleven".
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