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13130200013241 = 34376733337747
BaseRepresentation
bin1011111100010001110011…
…1010000101100110111001
31201111020100012210111111010
42333010130322011212321
53210111122200410431
643531533002424133
72523424411426623
oct277043472054671
951436305714433
1013130200013241
114202539670823
121580879502049
1374323212027c
1433570dcb7c13
1517b82ed58846
hexbf11ce859b9

13130200013241 has 4 divisors (see below), whose sum is σ = 17506933350992. Its totient is φ = 8753466675492.

The previous prime is 13130200013239. The next prime is 13130200013269. The reversal of 13130200013241 is 14231000203131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13130200013241 - 21 = 13130200013239 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13130200013221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2188366668871 + ... + 2188366668876.

It is an arithmetic number, because the mean of its divisors is an integer number (4376733337748).

Almost surely, 213130200013241 is an apocalyptic number.

It is an amenable number.

13130200013241 is a deficient number, since it is larger than the sum of its proper divisors (4376733337751).

13130200013241 is an equidigital number, since it uses as much as digits as its factorization.

13130200013241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4376733337750.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 13130200013241 its reverse (14231000203131), we get a palindrome (27361200216372).

The spelling of 13130200013241 in words is "thirteen trillion, one hundred thirty billion, two hundred million, thirteen thousand, two hundred forty-one".

Divisors: 1 3 4376733337747 13130200013241