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131302144441 = 1310100164957
BaseRepresentation
bin111101001001000110…
…1111011100110111001
3110112220200011000222201
41322102031323212321
54122401322110231
6140152552350201
712325534545556
oct1722215734671
9415820130881
10131302144441
1150759701566
12215449a5361
13c4c68b08c0
1464d83c7a2d
153637329161
hex1e9237b9b9

131302144441 has 4 divisors (see below), whose sum is σ = 141402309412. Its totient is φ = 121201979472.

The previous prime is 131302144423. The next prime is 131302144451. The reversal of 131302144441 is 144441203131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 144441203131 = 436333105937.

It can be written as a sum of positive squares in 2 ways, for example, as 70704937216 + 60597207225 = 265904^2 + 246165^2 .

It is a cyclic number.

It is not a de Polignac number, because 131302144441 - 211 = 131302142393 is a prime.

It is not an unprimeable number, because it can be changed into a prime (131302144411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5050082466 + ... + 5050082491.

It is an arithmetic number, because the mean of its divisors is an integer number (35350577353).

Almost surely, 2131302144441 is an apocalyptic number.

It is an amenable number.

131302144441 is a deficient number, since it is larger than the sum of its proper divisors (10100164971).

131302144441 is a wasteful number, since it uses less digits than its factorization.

131302144441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10100164970.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 131302144441 its reverse (144441203131), we get a palindrome (275743347572).

The spelling of 131302144441 in words is "one hundred thirty-one billion, three hundred two million, one hundred forty-four thousand, four hundred forty-one".

Divisors: 1 13 10100164957 131302144441