13130222120433 has 16 divisors (see below), whose sum is σ = 21220561003200. Its totient is φ = 7957710375840.

The previous prime is 13130222120417. The next prime is 13130222120471. The reversal of 13130222120433 is 33402122203131.

13130222120433 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 0 + 2 + 221 + 2 + 0 + 433 = 666.

It is not a de Polignac number, because 13130222120433 - 2⁴ = 13130222120417 is a prime.

It is a super-2 number, since 2×13130222120433² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 13130222120397 and 13130222120406.

It is not an unprimeable number, because it can be changed into a prime (13130222140433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22104750748 + ... + 22104751341.

It is an arithmetic number, because the mean of its divisors is an integer number (1326285062700).

Almost surely, 2^{13130222120433} is an apocalyptic number.

It is an amenable number.

13130222120433 is a deficient number, since it is larger than the sum of its proper divisors (8090338882767).

13130222120433 is a wasteful number, since it uses less digits than its factorization.

13130222120433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44209502109 (or 44209502103 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 13130222120433 its reverse (33402122203131), we get a palindrome (46532344323564).

The spelling of 13130222120433 in words is "thirteen trillion, one hundred thirty billion, two hundred twenty-two million, one hundred twenty thousand, four hundred thirty-three".