1313040121 has 4 divisors (see below), whose sum is σ = 1325311632. Its totient is φ = 1300768612.

The previous prime is 1313040107. The next prime is 1313040137. The reversal of 1313040121 is 1210403131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1313040121 - 2¹⁷ = 1312909049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313040095 and 1313040104.

It is not an unprimeable number, because it can be changed into a prime (1313040151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6135595 + ... + 6135808.

It is an arithmetic number, because the mean of its divisors is an integer number (331327908).

Almost surely, 2^1313040121 is an apocalyptic number.

It is an amenable number.

1313040121 is a deficient number, since it is larger than the sum of its proper divisors (12271511).

1313040121 is a wasteful number, since it uses less digits than its factorization.

1313040121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12271510.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1313040121 is about 36235.8954767231. The cubic root of 1313040121 is about 1095.0299529625.

Adding to 1313040121 its reverse (1210403131), we get a palindrome (2523443252).

The spelling of 1313040121 in words is "one billion, three hundred thirteen million, forty thousand, one hundred twenty-one".