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13130434043403 = 34376811347801
BaseRepresentation
bin1011111100010010101011…
…0110110101111000001011
31201111020221112011110111220
42333010222312311320023
53210112112103342103
643532012122453123
72523433252566405
oct277045266657013
951436845143456
1013130434043403
114202649787086
1215809239641a3
1374326b760a61
14335732dd7b75
1517b845685c53
hexbf12adb5e0b

13130434043403 has 4 divisors (see below), whose sum is σ = 17507245391208. Its totient is φ = 8753622695600.

The previous prime is 13130434043401. The next prime is 13130434043417. The reversal of 13130434043403 is 30434043403131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13130434043403 - 21 = 13130434043401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13130434043401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2188405673898 + ... + 2188405673903.

It is an arithmetic number, because the mean of its divisors is an integer number (4376811347802).

Almost surely, 213130434043403 is an apocalyptic number.

13130434043403 is a deficient number, since it is larger than the sum of its proper divisors (4376811347805).

13130434043403 is an equidigital number, since it uses as much as digits as its factorization.

13130434043403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4376811347804.

The product of its (nonzero) digits is 62208, while the sum is 33.

Adding to 13130434043403 its reverse (30434043403131), we get a palindrome (43564477446534).

The spelling of 13130434043403 in words is "thirteen trillion, one hundred thirty billion, four hundred thirty-four million, forty-three thousand, four hundred three".

Divisors: 1 3 4376811347801 13130434043403