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1313087443961 = 2027647798443
BaseRepresentation
bin10011000110111010000…
…111000101001111111001
311122112022022200111020212
4103012322013011033321
5133003200341201321
62443120221000505
7163603350054566
oct23067207051771
94575268614225
101313087443961
114669716a2587
1219259a3b3135
1396a92634817
14477a779786d
1524252d9b55b
hex131ba1c53f9

1313087443961 has 4 divisors (see below), whose sum is σ = 1313735244432. Its totient is φ = 1312439643492.

The previous prime is 1313087443937. The next prime is 1313087443979. The reversal of 1313087443961 is 1693447803131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313087443961 - 230 = 1312013702137 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313087443061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 323897195 + ... + 323901248.

It is an arithmetic number, because the mean of its divisors is an integer number (328433811108).

Almost surely, 21313087443961 is an apocalyptic number.

It is an amenable number.

1313087443961 is a deficient number, since it is larger than the sum of its proper divisors (647800471).

1313087443961 is an equidigital number, since it uses as much as digits as its factorization.

1313087443961 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 647800470.

The product of its (nonzero) digits is 1306368, while the sum is 50.

The spelling of 1313087443961 in words is "one trillion, three hundred thirteen billion, eighty-seven million, four hundred forty-three thousand, nine hundred sixty-one".

Divisors: 1 2027 647798443 1313087443961