13131000433 has 4 divisors (see below), whose sum is σ = 13131305460. Its totient is φ = 13130695408.

The previous prime is 13131000419. The next prime is 13131000457. The reversal of 13131000433 is 33400013131.

13131000433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4837619809 + 8293380624 = 69553^2 + 91068^2 .

It is a cyclic number.

It is not a de Polignac number, because 13131000433 - 2⁵ = 13131000401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13131000433.

It is not an unprimeable number, because it can be changed into a prime (13131000733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74710 + ... + 178447.

It is an arithmetic number, because the mean of its divisors is an integer number (3282826365).

Almost surely, 2^13131000433 is an apocalyptic number.

It is an amenable number.

13131000433 is a deficient number, since it is larger than the sum of its proper divisors (305027).

13131000433 is an equidigital number, since it uses as much as digits as its factorization.

13131000433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 305026.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 13131000433 its reverse (33400013131), we get a palindrome (46531013564).

The spelling of 13131000433 in words is "thirteen billion, one hundred thirty-one million, four hundred thirty-three", and thus it is an aban number.