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13131010203 = 34377003401
BaseRepresentation
bin11000011101010101…
…10101000010011011
31020220010022102200020
430032222311002123
5203343014311303
610010551041523
7643253513403
oct141652650233
936803272606
1013131010203
115629127353
1226656702a3
13131358222c
148c7d0d803
1551cbcea53
hex30eab509b

13131010203 has 4 divisors (see below), whose sum is σ = 17508013608. Its totient is φ = 8754006800.

The previous prime is 13131010159. The next prime is 13131010229. The reversal of 13131010203 is 30201013131.

13131010203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13131010203 - 214 = 13130993819 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13131010003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2188501698 + ... + 2188501703.

It is an arithmetic number, because the mean of its divisors is an integer number (4377003402).

Almost surely, 213131010203 is an apocalyptic number.

13131010203 is a deficient number, since it is larger than the sum of its proper divisors (4377003405).

13131010203 is an equidigital number, since it uses as much as digits as its factorization.

13131010203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4377003404.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13131010203 its reverse (30201013131), we get a palindrome (43332023334).

The spelling of 13131010203 in words is "thirteen billion, one hundred thirty-one million, ten thousand, two hundred three".

Divisors: 1 3 4377003401 13131010203