13131011311121 has 8 divisors (see below), whose sum is σ = 14327180428800. Its totient is φ = 11935248996240.

The previous prime is 13131011311097. The next prime is 13131011311219. The reversal of 13131011311121 is 12111311013131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13131011311121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13131011311093 and 13131011311102.

It is not an unprimeable number, because it can be changed into a prime (13131011311321) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 101633201 + ... + 101762318.

It is an arithmetic number, because the mean of its divisors is an integer number (1790897553600).

Almost surely, 2^{13131011311121} is an apocalyptic number.

13131011311121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13131011311121 is a deficient number, since it is larger than the sum of its proper divisors (1196169117679).

13131011311121 is a wasteful number, since it uses less digits than its factorization.

13131011311121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 203401399.

The product of its (nonzero) digits is 54, while the sum is 20.

Adding to 13131011311121 its reverse (12111311013131), we get a palindrome (25242322324252).

The spelling of 13131011311121 in words is "thirteen trillion, one hundred thirty-one billion, eleven million, three hundred eleven thousand, one hundred twenty-one".