13131045031241 has 4 divisors (see below), whose sum is σ = 13137391599300. Its totient is φ = 13124698463184.

The previous prime is 13131045031229. The next prime is 13131045031249. The reversal of 13131045031241 is 14213054013131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3558184279225 + 9572860752016 = 1886315^2 + 3094004^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13131045031241 is a prime.

It is a super-2 number, since 2×13131045031241² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13131045031249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3173280926 + ... + 3173285063.

It is an arithmetic number, because the mean of its divisors is an integer number (3284347899825).

Almost surely, 2^{13131045031241} is an apocalyptic number.

It is an amenable number.

13131045031241 is a deficient number, since it is larger than the sum of its proper divisors (6346568059).

13131045031241 is an equidigital number, since it uses as much as digits as its factorization.

13131045031241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6346568058.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 13131045031241 its reverse (14213054013131), we get a palindrome (27344099044372).

The spelling of 13131045031241 in words is "thirteen trillion, one hundred thirty-one billion, forty-five million, thirty-one thousand, two hundred forty-one".