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13131102331 = 19691110649
BaseRepresentation
bin11000011101010110…
…01011100001111011
31020220010111010001101
430032223023201323
5203343030233311
610010553032231
7643254346114
oct141653134173
936803433041
1013131102331
11562918a596
1226656b5677
1313135b5149
148c7d3520b
1551cbebec1
hex30eacb87b

13131102331 has 4 divisors (see below), whose sum is σ = 13822213000. Its totient is φ = 12439991664.

The previous prime is 13131102319. The next prime is 13131102337. The reversal of 13131102331 is 13320113131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13320113131 = 131024624087.

It is a cyclic number.

It is not a de Polignac number, because 13131102331 - 213 = 13131094139 is a prime.

It is a super-2 number, since 2×131311023312 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 691110649 = 13131102331 / (1 + 3 + 1 + 3 + 1 + 1 + 0 + 2 + 3 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13131102299 and 13131102308.

It is not an unprimeable number, because it can be changed into a prime (13131102337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345555306 + ... + 345555343.

It is an arithmetic number, because the mean of its divisors is an integer number (3455553250).

Almost surely, 213131102331 is an apocalyptic number.

13131102331 is a deficient number, since it is larger than the sum of its proper divisors (691110669).

13131102331 is an equidigital number, since it uses as much as digits as its factorization.

13131102331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 691110668.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13131102331 its reverse (13320113131), we get a palindrome (26451215462).

The spelling of 13131102331 in words is "thirteen billion, one hundred thirty-one million, one hundred two thousand, three hundred thirty-one".

Divisors: 1 19 691110649 13131102331