Base | Representation |
---|---|
bin | 1011111100010101101110… |
… | …1100001001111000101001 |
3 | 1201111100001121210022001211 |
4 | 2333011123230021320221 |
5 | 3210120301322402403 |
6 | 43532225310513121 |
7 | 2523462461431462 |
oct | 277053354117051 |
9 | 51440047708054 |
10 | 13131253325353 |
11 | 4202a2a1977a9 |
12 | 1580b122057a1 |
13 | 74336c405287 |
14 | 3357adb41d69 |
15 | 17b89256b06d |
hex | bf15bb09e29 |
13131253325353 has 8 divisors (see below), whose sum is σ = 13148747290368. Its totient is φ = 13113770647824.
The previous prime is 13131253325341. The next prime is 13131253325381. The reversal of 13131253325353 is 35352335213131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13131253325353 - 25 = 13131253325321 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13131253325303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 492351 + ... + 5148292.
It is an arithmetic number, because the mean of its divisors is an integer number (1643593411296).
Almost surely, 213131253325353 is an apocalyptic number.
It is an amenable number.
13131253325353 is a deficient number, since it is larger than the sum of its proper divisors (17493965015).
13131253325353 is a wasteful number, since it uses less digits than its factorization.
13131253325353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5643743.
The product of its digits is 364500, while the sum is 40.
Adding to 13131253325353 its reverse (35352335213131), we get a palindrome (48483588538484).
The spelling of 13131253325353 in words is "thirteen trillion, one hundred thirty-one billion, two hundred fifty-three million, three hundred twenty-five thousand, three hundred fifty-three".
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