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131313103113 = 343771034371
BaseRepresentation
bin111101001001011011…
…1101111000100001001
3110112221102202210110110
41322102313233010021
54122412123244423
6140154023304533
712326026650213
oct1722267570411
9415842683413
10131313103113
1150764906a15
12215485ab149
13c4c8c4991a
1464d9a3b5b3
153638291193
hex1e92def109

131313103113 has 4 divisors (see below), whose sum is σ = 175084137488. Its totient is φ = 87542068740.

The previous prime is 131313103099. The next prime is 131313103121. The reversal of 131313103113 is 311301313131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-131313103113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131313103113.

It is not an unprimeable number, because it can be changed into a prime (131313103123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21885517183 + ... + 21885517188.

It is an arithmetic number, because the mean of its divisors is an integer number (43771034372).

Almost surely, 2131313103113 is an apocalyptic number.

It is an amenable number.

131313103113 is a deficient number, since it is larger than the sum of its proper divisors (43771034375).

131313103113 is an equidigital number, since it uses as much as digits as its factorization.

131313103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43771034374.

The product of its (nonzero) digits is 243, while the sum is 21.

Adding to 131313103113 its reverse (311301313131), we get a palindrome (442614416244).

The spelling of 131313103113 in words is "one hundred thirty-one billion, three hundred thirteen million, one hundred three thousand, one hundred thirteen".

Divisors: 1 3 43771034371 131313103113