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1313140402211 = 11119376400201
BaseRepresentation
bin10011000110111101010…
…001000110100000100011
311122112110000100001022112
4103012331101012200203
5133003302420332321
62443125352025535
7163604562153041
oct23067521064043
94575400301275
101313140402211
11466999583930
121925b40922ab
1396aa05b7571
14477b0821391
152425785ca5b
hex131bd446823

1313140402211 has 4 divisors (see below), whose sum is σ = 1432516802424. Its totient is φ = 1193764002000.

The previous prime is 1313140402121. The next prime is 1313140402243. The reversal of 1313140402211 is 1122040413131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313140402211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313140402261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59688200090 + ... + 59688200111.

It is an arithmetic number, because the mean of its divisors is an integer number (358129200606).

Almost surely, 21313140402211 is an apocalyptic number.

1313140402211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1313140402211 is a deficient number, since it is larger than the sum of its proper divisors (119376400213).

1313140402211 is a wasteful number, since it uses less digits than its factorization.

1313140402211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119376400212.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1313140402211 its reverse (1122040413131), we get a palindrome (2435180815342).

The spelling of 1313140402211 in words is "one trillion, three hundred thirteen billion, one hundred forty million, four hundred two thousand, two hundred eleven".

Divisors: 1 11 119376400201 1313140402211