Base | Representation |
---|---|
bin | 1011111100010110011001… |
… | …0101111010011010101011 |
3 | 1201111100112002002011020111 |
4 | 2333011212111322122223 |
5 | 3210121133100403303 |
6 | 43532255133235151 |
7 | 2523500061502624 |
oct | 277054625723253 |
9 | 51440462064214 |
10 | 13131432044203 |
11 | 4203011064930 |
12 | 1580b62032ab7 |
13 | 74339a44ac85 |
14 | 3357c9784a4b |
15 | 17b8a30beb6d |
hex | bf16657a6ab |
13131432044203 has 8 divisors (see below), whose sum is σ = 14567998570560. Its totient is φ = 11735332180680.
The previous prime is 13131432044197. The next prime is 13131432044243. The reversal of 13131432044203 is 30244023413131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13131432044203 - 213 = 13131432036011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13131432044243) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10116665025 + ... + 10116666322.
It is an arithmetic number, because the mean of its divisors is an integer number (1820999821320).
Almost surely, 213131432044203 is an apocalyptic number.
13131432044203 is a deficient number, since it is larger than the sum of its proper divisors (1436566526357).
13131432044203 is a wasteful number, since it uses less digits than its factorization.
13131432044203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20233331417.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13131432044203 its reverse (30244023413131), we get a palindrome (43375455457334).
The spelling of 13131432044203 in words is "thirteen trillion, one hundred thirty-one billion, four hundred thirty-two million, forty-four thousand, two hundred three".
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