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13132001310011 = 29269344866127
BaseRepresentation
bin1011111100011000100001…
…0001011111010100111011
31201111101222202020212010022
42333012020101133110323
53210123314313410021
643532431430441055
72523520143254663
oct277061021372473
951441882225108
1013132001310011
114203283430741
1215810a080318b
1374345b37564c
1433584120b1a3
1517b8d806b1ab
hexbf18845f53b

13132001310011 has 4 divisors (see below), whose sum is σ = 13132046468832. Its totient is φ = 13131956151192.

The previous prime is 13132001309993. The next prime is 13132001310017. The reversal of 13132001310011 is 11001310023131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13132001310011 is a prime.

It is a super-2 number, since 2×131320013100112 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13132001310017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22140371 + ... + 22725756.

It is an arithmetic number, because the mean of its divisors is an integer number (3283011617208).

Almost surely, 213132001310011 is an apocalyptic number.

13132001310011 is a deficient number, since it is larger than the sum of its proper divisors (45158821).

13132001310011 is an equidigital number, since it uses as much as digits as its factorization.

13132001310011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45158820.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13132001310011 its reverse (11001310023131), we get a palindrome (24133311333142).

The spelling of 13132001310011 in words is "thirteen trillion, one hundred thirty-two billion, one million, three hundred ten thousand, eleven".

Divisors: 1 292693 44866127 13132001310011