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13132004424443 = 59222576346177
BaseRepresentation
bin1011111100011000100001…
…1101010111101011111011
31201111101222222010002022122
42333012020131113223323
53210123321113040233
643532432021311455
72523520211605652
oct277061035275373
951441888102278
1013132004424443
114203285168653
1215810a186558b
1374345bbc60c8
143358417bc199
1517b8d8483d98
hexbf188757afb

13132004424443 has 4 divisors (see below), whose sum is σ = 13354580770680. Its totient is φ = 12909428078208.

The previous prime is 13132004424437. The next prime is 13132004424493. The reversal of 13132004424443 is 34442440023131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13132004424443 - 212 = 13132004420347 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13132004424493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111288173030 + ... + 111288173147.

It is an arithmetic number, because the mean of its divisors is an integer number (3338645192670).

Almost surely, 213132004424443 is an apocalyptic number.

13132004424443 is a deficient number, since it is larger than the sum of its proper divisors (222576346237).

13132004424443 is an equidigital number, since it uses as much as digits as its factorization.

13132004424443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 222576346236.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 13132004424443 its reverse (34442440023131), we get a palindrome (47574444447574).

The spelling of 13132004424443 in words is "thirteen trillion, one hundred thirty-two billion, four million, four hundred twenty-four thousand, four hundred forty-three".

Divisors: 1 59 222576346177 13132004424443