131320113 has 4 divisors (see below), whose sum is σ = 175093488. Its totient is φ = 87546740.

The previous prime is 131320093. The next prime is 131320139. The reversal of 131320113 is 311023131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311023131 = 3 ⋅103674377.

It is a cyclic number.

It is not a de Polignac number, because 131320113 - 2⁵ = 131320081 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131320092 and 131320101.

It is not an unprimeable number, because it can be changed into a prime (131320183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21886683 + ... + 21886688.

It is an arithmetic number, because the mean of its divisors is an integer number (43773372).

Almost surely, 2^131320113 is an apocalyptic number.

It is an amenable number.

131320113 is a deficient number, since it is larger than the sum of its proper divisors (43773375).

131320113 is an equidigital number, since it uses as much as digits as its factorization.

131320113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43773374.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 131320113 is about 11459.4988110301. The cubic root of 131320113 is about 508.2886544864.

Adding to 131320113 its reverse (311023131), we get a palindrome (442343244).

The spelling of 131320113 in words is "one hundred thirty-one million, three hundred twenty thousand, one hundred thirteen".