Base | Representation |
---|---|
bin | 10011000111000000111… |
… | …100001010011101000011 |
3 | 11122112121022021200001202 |
4 | 103013000330022131003 |
5 | 133003414204202321 |
6 | 2443135432451415 |
7 | 163606241005142 |
oct | 23070074123503 |
9 | 4575538250052 |
10 | 1313202022211 |
11 | 466a20340952 |
12 | 192610849b6b |
13 | 96ab02b09c1 |
14 | 477b8aa1759 |
15 | 2425ce8070b |
hex | 131c0f0a743 |
1313202022211 has 4 divisors (see below), whose sum is σ = 1313204611800. Its totient is φ = 1313199432624.
The previous prime is 1313202022177. The next prime is 1313202022217. The reversal of 1313202022211 is 1122202023131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1313202022211 - 26 = 1313202022147 is a prime.
It is a super-2 number, since 2×13132020222112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1313202022217) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 256706 + ... + 1640823.
It is an arithmetic number, because the mean of its divisors is an integer number (328301152950).
Almost surely, 21313202022211 is an apocalyptic number.
1313202022211 is a deficient number, since it is larger than the sum of its proper divisors (2589589).
1313202022211 is an equidigital number, since it uses as much as digits as its factorization.
1313202022211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2589588.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 1313202022211 its reverse (1122202023131), we get a palindrome (2435404045342).
The spelling of 1313202022211 in words is "one trillion, three hundred thirteen billion, two hundred two million, twenty-two thousand, two hundred eleven".
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