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13132021403 = 106119876229
BaseRepresentation
bin11000011101011101…
…01011111010011011
31020220012012210210002
430032232223322123
5203343244141103
610011024443215
7643265224454
oct141656537233
936805183702
1013132021403
115629758056
122665a7950b
131313847587
148c80d412b
1551cd2e488
hex30ebabe9b

13132021403 has 8 divisors (see below), whose sum is σ = 13153124880. Its totient is φ = 13110936480.

The previous prime is 13132021393. The next prime is 13132021423. The reversal of 13132021403 is 30412023131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13132021403 - 230 = 12058279579 is a prime.

It is a super-3 number, since 3×131320214033 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13132021423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2105093 + ... + 2111321.

It is an arithmetic number, because the mean of its divisors is an integer number (1644140610).

Almost surely, 213132021403 is an apocalyptic number.

13132021403 is a deficient number, since it is larger than the sum of its proper divisors (21103477).

13132021403 is a wasteful number, since it uses less digits than its factorization.

13132021403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9277.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13132021403 its reverse (30412023131), we get a palindrome (43544044534).

The spelling of 13132021403 in words is "thirteen billion, one hundred thirty-two million, twenty-one thousand, four hundred three".

Divisors: 1 1061 1987 6229 2108207 6608969 12377023 13132021403