Base | Representation |
---|---|
bin | 11101110110111101100100… |
… | …000001100100111011100011 |
3 | 122012222002122201102200110112 |
4 | 131312331210001210323203 |
5 | 114203022440110211321 |
6 | 1143143414153521535 |
7 | 36442402350626633 |
oct | 3566754401447343 |
9 | 565862581380415 |
10 | 131320303210211 |
11 | 3892a69a715795 |
12 | 1288a907a132ab |
13 | 58375b3b0a27b |
14 | 245dd17dda6c3 |
15 | 102ae20b7ea5b |
hex | 776f64064ee3 |
131320303210211 has 8 divisors (see below), whose sum is σ = 131769991394160. Its totient is φ = 130870625203872.
The previous prime is 131320303210171. The next prime is 131320303210289. The reversal of 131320303210211 is 112012303023131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131320303210211 - 210 = 131320303209187 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131320303210111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23770661 + ... + 28769513.
It is an arithmetic number, because the mean of its divisors is an integer number (16471248924270).
Almost surely, 2131320303210211 is an apocalyptic number.
131320303210211 is a deficient number, since it is larger than the sum of its proper divisors (449688183949).
131320303210211 is an equidigital number, since it uses as much as digits as its factorization.
131320303210211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5088805.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 131320303210211 its reverse (112012303023131), we get a palindrome (243332606233342).
The spelling of 131320303210211 in words is "one hundred thirty-one trillion, three hundred twenty billion, three hundred three million, two hundred ten thousand, two hundred eleven".
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