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131321104451 = 2361401233417
BaseRepresentation
bin111101001001101011…
…0010000100001000011
3110112221222211022020022
41322103112100201003
54122421200320301
6140154511004055
712326154653555
oct1722326204103
9415858738208
10131321104451
1150769381499
122154b20962b
13c4ca7bb844
1464dab214d5
153638d21d1b
hex1e93590843

131321104451 has 16 divisors (see below), whose sum is σ = 139625045568. Its totient is φ = 123243648000.

The previous prime is 131321104417. The next prime is 131321104457. The reversal of 131321104451 is 154401123131.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131321104451 is a prime.

It is a super-2 number, since 2×1313211044512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131321104451.

It is not an unprimeable number, because it can be changed into a prime (131321104457) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 445895 + ... + 679311.

It is an arithmetic number, because the mean of its divisors is an integer number (8726565348).

Almost surely, 2131321104451 is an apocalyptic number.

131321104451 is a deficient number, since it is larger than the sum of its proper divisors (8303941117).

131321104451 is a wasteful number, since it uses less digits than its factorization.

131321104451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 233902.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 131321104451 its reverse (154401123131), we get a palindrome (285722227582).

The spelling of 131321104451 in words is "one hundred thirty-one billion, three hundred twenty-one million, one hundred four thousand, four hundred fifty-one".

Divisors: 1 23 61 401 1403 9223 24461 233417 562603 5368591 14238437 93600217 327484051 2152804991 5709613237 131321104451