1313213010033 has 4 divisors (see below), whose sum is σ = 1750950680048. Its totient is φ = 875475340020.

The previous prime is 1313213010001. The next prime is 1313213010037. The reversal of 1313213010033 is 3300103123131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1313213010033 - 2⁵ = 1313213010001 is a prime.

It is a super-2 number, since 2×1313213010033² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1313213009991 and 1313213010009.

It is not an unprimeable number, because it can be changed into a prime (1313213010037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218868835003 + ... + 218868835008.

It is an arithmetic number, because the mean of its divisors is an integer number (437737670012).

Almost surely, 2^{1313213010033} is an apocalyptic number.

It is an amenable number.

1313213010033 is a deficient number, since it is larger than the sum of its proper divisors (437737670015).

1313213010033 is an equidigital number, since it uses as much as digits as its factorization.

1313213010033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 437737670014.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 1313213010033 its reverse (3300103123131), we get a palindrome (4613316133164).

The spelling of 1313213010033 in words is "one trillion, three hundred thirteen billion, two hundred thirteen million, ten thousand, thirty-three".