1313220013201 has 4 divisors (see below), whose sum is σ = 1343760013552. Its totient is φ = 1282680012852.

The previous prime is 1313220013187. The next prime is 1313220013211. The reversal of 1313220013201 is 1023100223131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313220013201 - 2⁵ = 1313220013169 is a prime.

It is a super-2 number, since 2×1313220013201² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313220013211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15270000111 + ... + 15270000196.

It is an arithmetic number, because the mean of its divisors is an integer number (335940003388).

Almost surely, 2^{1313220013201} is an apocalyptic number.

It is an amenable number.

1313220013201 is a deficient number, since it is larger than the sum of its proper divisors (30540000351).

1313220013201 is an equidigital number, since it uses as much as digits as its factorization.

1313220013201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30540000350.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1313220013201 its reverse (1023100223131), we get a palindrome (2336320236332).

The spelling of 1313220013201 in words is "one trillion, three hundred thirteen billion, two hundred twenty million, thirteen thousand, two hundred one".