Base | Representation |
---|---|
bin | 10011000111000010000… |
… | …101110001110110110001 |
3 | 11122112122122121002210212 |
4 | 103013002011301312301 |
5 | 133003434124220423 |
6 | 2443141402233505 |
7 | 163606564021223 |
oct | 23070205616661 |
9 | 4575578532725 |
10 | 1313221320113 |
11 | 466a3022172a |
12 | 1926171b5895 |
13 | 96ab42a9691 |
14 | 477bb486413 |
15 | 2425e9e3578 |
hex | 131c2171db1 |
1313221320113 has 8 divisors (see below), whose sum is σ = 1358585110080. Its totient is φ = 1267862883280.
The previous prime is 1313221320049. The next prime is 1313221320119. The reversal of 1313221320113 is 3110231223131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1313221320113 - 26 = 1313221320049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1313221320119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 835973 + ... + 1823538.
It is an arithmetic number, because the mean of its divisors is an integer number (169823138760).
Almost surely, 21313221320113 is an apocalyptic number.
It is an amenable number.
1313221320113 is a deficient number, since it is larger than the sum of its proper divisors (45363789967).
1313221320113 is a wasteful number, since it uses less digits than its factorization.
1313221320113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2676567.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1313221320113 its reverse (3110231223131), we get a palindrome (4423452543244).
The spelling of 1313221320113 in words is "one trillion, three hundred thirteen billion, two hundred twenty-one million, three hundred twenty thousand, one hundred thirteen".
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