13132253113001 has 4 divisors (see below), whose sum is σ = 14326094305104. Its totient is φ = 11938411920900.

The previous prime is 13132253112997. The next prime is 13132253113003. The reversal of 13132253113001 is 10031135223131.

13132253113001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13132253113001 - 2² = 13132253112997 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13132253113003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596920596035 + ... + 596920596056.

It is an arithmetic number, because the mean of its divisors is an integer number (3581523576276).

Almost surely, 2^{13132253113001} is an apocalyptic number.

13132253113001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13132253113001 is a deficient number, since it is larger than the sum of its proper divisors (1193841192103).

13132253113001 is a wasteful number, since it uses less digits than its factorization.

13132253113001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1193841192102.

The product of its (nonzero) digits is 1620, while the sum is 26.

Adding to 13132253113001 its reverse (10031135223131), we get a palindrome (23163388336132).

The spelling of 13132253113001 in words is "thirteen trillion, one hundred thirty-two billion, two hundred fifty-three million, one hundred thirteen thousand, one".