131323411433 has 4 divisors (see below), whose sum is σ = 131443782288. Its totient is φ = 131203040580.

The previous prime is 131323411421. The next prime is 131323411451. The reversal of 131323411433 is 334114323131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131323411433 - 2⁶ = 131323411369 is a prime.

It is a super-2 number, since 2×131323411433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131323411396 and 131323411405.

It is not an unprimeable number, because it can be changed into a prime (131323410433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60183791 + ... + 60185972.

It is an arithmetic number, because the mean of its divisors is an integer number (32860945572).

Almost surely, 2^131323411433 is an apocalyptic number.

It is an amenable number.

131323411433 is a deficient number, since it is larger than the sum of its proper divisors (120370855).

131323411433 is a wasteful number, since it uses less digits than its factorization.

131323411433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120370854.

The product of its digits is 7776, while the sum is 29.

Adding to 131323411433 its reverse (334114323131), we get a palindrome (465437734564).

The spelling of 131323411433 in words is "one hundred thirty-one billion, three hundred twenty-three million, four hundred eleven thousand, four hundred thirty-three".