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1313243411203 = 2356995571697
BaseRepresentation
bin10011000111000011011…
…010000011001100000011
311122112201012011110002101
4103013003122003030003
5133004010303124303
62443143511531231
7163610252546563
oct23070332031403
94575635143071
101313243411203
11466a41740029
12192622689b17
1396ab8a42829
14477c0396da3
1524261908d1d
hex131c3683303

1313243411203 has 4 divisors (see below), whose sum is σ = 1313249218600. Its totient is φ = 1313237603808.

The previous prime is 1313243411083. The next prime is 1313243411231. The reversal of 1313243411203 is 3021143423131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313243411203 - 29 = 1313243410691 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313243411003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2550150 + ... + 3021547.

It is an arithmetic number, because the mean of its divisors is an integer number (328312304650).

Almost surely, 21313243411203 is an apocalyptic number.

1313243411203 is a deficient number, since it is larger than the sum of its proper divisors (5807397).

1313243411203 is an equidigital number, since it uses as much as digits as its factorization.

1313243411203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5807396.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1313243411203 its reverse (3021143423131), we get a palindrome (4334386834334).

The spelling of 1313243411203 in words is "one trillion, three hundred thirteen billion, two hundred forty-three million, four hundred eleven thousand, two hundred three".

Divisors: 1 235699 5571697 1313243411203