Base | Representation |
---|---|
bin | 11000011101100101… |
… | …10011001111100011 |
3 | 1020220021020121100020 |
4 | 30032302303033203 |
5 | 203344033200003 |
6 | 10011103524523 |
7 | 643310336202 |
oct | 141662631743 |
9 | 36807217306 |
10 | 13133100003 |
11 | 562a324461 |
12 | 26662b9743 |
13 | 1313b344ba |
14 | 8c82d5239 |
15 | 51ce93d53 |
hex | 30ecb33e3 |
13133100003 has 4 divisors (see below), whose sum is σ = 17510800008. Its totient is φ = 8755400000.
The previous prime is 13133099989. The next prime is 13133100007. The reversal of 13133100003 is 30000133131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13133100003 - 25 = 13133099971 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13133100007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2188849998 + ... + 2188850003.
It is an arithmetic number, because the mean of its divisors is an integer number (4377700002).
Almost surely, 213133100003 is an apocalyptic number.
13133100003 is a deficient number, since it is larger than the sum of its proper divisors (4377700005).
13133100003 is an equidigital number, since it uses as much as digits as its factorization.
13133100003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4377700004.
The product of its (nonzero) digits is 81, while the sum is 15.
Adding to 13133100003 its reverse (30000133131), we get a palindrome (43133233134).
The spelling of 13133100003 in words is "thirteen billion, one hundred thirty-three million, one hundred thousand, three".
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