13133113301233 has 4 divisors (see below), whose sum is σ = 13133146658800. Its totient is φ = 13133079943668.

The previous prime is 13133113301137. The next prime is 13133113301267. The reversal of 13133113301233 is 33210331133131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13133113301233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13133113301293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16081083 + ... + 16878016.

It is an arithmetic number, because the mean of its divisors is an integer number (3283286664700).

Almost surely, 2^{13133113301233} is an apocalyptic number.

It is an amenable number.

13133113301233 is a deficient number, since it is larger than the sum of its proper divisors (33357567).

13133113301233 is an equidigital number, since it uses as much as digits as its factorization.

13133113301233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33357566.

The product of its (nonzero) digits is 4374, while the sum is 28.

Adding to 13133113301233 its reverse (33210331133131), we get a palindrome (46343444434364).

The spelling of 13133113301233 in words is "thirteen trillion, one hundred thirty-three billion, one hundred thirteen million, three hundred one thousand, two hundred thirty-three".