1313313000233 has 4 divisors (see below), whose sum is σ = 1414337077188. Its totient is φ = 1212288923280.

The previous prime is 1313313000229. The next prime is 1313313000239. The reversal of 1313313000233 is 3320003133131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 86984884624 + 1226328115609 = 294932^2 + 1107397^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313313000233 - 2² = 1313313000229 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313313000199 and 1313313000208.

It is not an unprimeable number, because it can be changed into a prime (1313313000239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50512038458 + ... + 50512038483.

It is an arithmetic number, because the mean of its divisors is an integer number (353584269297).

Almost surely, 2^{1313313000233} is an apocalyptic number.

1313313000233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1313313000233 is a deficient number, since it is larger than the sum of its proper divisors (101024076955).

1313313000233 is a wasteful number, since it uses less digits than its factorization.

1313313000233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 101024076954.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 1313313000233 its reverse (3320003133131), we get a palindrome (4633316133364).

The spelling of 1313313000233 in words is "one trillion, three hundred thirteen billion, three hundred thirteen million, two hundred thirty-three", and thus it is an aban number.