Base | Representation |
---|---|
bin | 11101110111001000111100… |
… | …111000111010101001110011 |
3 | 122020000021012221011201011121 |
4 | 131313020330320322221303 |
5 | 114203223011032432410 |
6 | 1143153155421123111 |
7 | 36443314363632031 |
oct | 3567107470725163 |
9 | 566007187151147 |
10 | 131332531530355 |
11 | 389348a52426a1 |
12 | 1289115b0b9497 |
13 | 58387b236356c |
14 | 246075808d551 |
15 | 102b3d94a09da |
hex | 77723ce3aa73 |
131332531530355 has 4 divisors (see below), whose sum is σ = 157599037836432. Its totient is φ = 105066025224280.
The previous prime is 131332531530329. The next prime is 131332531530377. The reversal of 131332531530355 is 553035135233131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 131332531530355 - 243 = 122536438508147 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13133253153031 + ... + 13133253153040.
It is an arithmetic number, because the mean of its divisors is an integer number (39399759459108).
Almost surely, 2131332531530355 is an apocalyptic number.
131332531530355 is a deficient number, since it is larger than the sum of its proper divisors (26266506306077).
131332531530355 is an equidigital number, since it uses as much as digits as its factorization.
131332531530355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26266506306076.
The product of its (nonzero) digits is 911250, while the sum is 43.
Adding to 131332531530355 its reverse (553035135233131), we get a palindrome (684367666763486).
The spelling of 131332531530355 in words is "one hundred thirty-one trillion, three hundred thirty-two billion, five hundred thirty-one million, five hundred thirty thousand, three hundred fifty-five".
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