1313331333131 has 4 divisors (see below), whose sum is σ = 1313334586200. Its totient is φ = 1313328080064.

The previous prime is 1313331333113. The next prime is 1313331333161.

1313331333131 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1313331333131 - 2³⁸ = 1038453426187 is a prime.

It is a super-2 number, since 2×1313331333131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313331333094 and 1313331333103.

It is not an unprimeable number, because it can be changed into a prime (1313331333161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 918101 + ... + 1862678.

It is an arithmetic number, because the mean of its divisors is an integer number (328333646550).

Almost surely, 2^{1313331333131} is an apocalyptic number.

1313331333131 is a deficient number, since it is larger than the sum of its proper divisors (3253069).

1313331333131 is an equidigital number, since it uses as much as digits as its factorization.

1313331333131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3253068.

The product of its digits is 6561, while the sum is 29.

The spelling of 1313331333131 in words is "one trillion, three hundred thirteen billion, three hundred thirty-one million, three hundred thirty-three thousand, one hundred thirty-one".