Base | Representation |
---|---|
bin | 1011111100011110010010… |
… | …1101100111101011110011 |
3 | 1201111112222211111121222021 |
4 | 2333013210231213223303 |
5 | 3210140003330010042 |
6 | 43533245351252311 |
7 | 2523603444435406 |
oct | 277074455475363 |
9 | 51445884447867 |
10 | 13133552188147 |
11 | 42039a9901406 |
12 | 158145407a097 |
13 | 74364776c911 |
14 | 33594b195d3d |
15 | 17b9792b5867 |
hex | bf1e4b67af3 |
13133552188147 has 4 divisors (see below), whose sum is σ = 13133982587056. Its totient is φ = 13133121789240.
The previous prime is 13133552188121. The next prime is 13133552188151. The reversal of 13133552188147 is 74188125533131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13133552188147 - 215 = 13133552155379 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13133552188094 and 13133552188103.
It is not an unprimeable number, because it can be changed into a prime (13133552188847) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 215153679 + ... + 215214712.
It is an arithmetic number, because the mean of its divisors is an integer number (3283495646764).
Almost surely, 213133552188147 is an apocalyptic number.
13133552188147 is a deficient number, since it is larger than the sum of its proper divisors (430398909).
13133552188147 is an equidigital number, since it uses as much as digits as its factorization.
13133552188147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 430398908.
The product of its digits is 2419200, while the sum is 52.
The spelling of 13133552188147 in words is "thirteen trillion, one hundred thirty-three billion, five hundred fifty-two million, one hundred eighty-eight thousand, one hundred forty-seven".
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