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13134005273 = 129831011631
BaseRepresentation
bin11000011101101100…
…10000010000011001
31020220022221121010202
430032312100100121
5203344301132043
610011135151545
7643321126364
oct141666202031
936808847122
1013134005273
11562a892614
1226666755b5
13131409056c
148c848d0db
1551d0c21b8
hex30ed90419

13134005273 has 4 divisors (see below), whose sum is σ = 13135029888. Its totient is φ = 13132980660.

The previous prime is 13134005267. The next prime is 13134005293. The reversal of 13134005273 is 37250043131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13134005273 is a prime.

It is a super-2 number, since 2×131340052732 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13134005263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 492833 + ... + 518798.

It is an arithmetic number, because the mean of its divisors is an integer number (3283757472).

Almost surely, 213134005273 is an apocalyptic number.

It is an amenable number.

13134005273 is a deficient number, since it is larger than the sum of its proper divisors (1024615).

13134005273 is a wasteful number, since it uses less digits than its factorization.

13134005273 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1024614.

The product of its (nonzero) digits is 7560, while the sum is 29.

The spelling of 13134005273 in words is "thirteen billion, one hundred thirty-four million, five thousand, two hundred seventy-three".

Divisors: 1 12983 1011631 13134005273