Base | Representation |
---|---|
bin | 111101001010001111… |
… | …0100011101101100001 |
3 | 110120000022111012211220 |
4 | 1322110132203231201 |
5 | 4122441023314231 |
6 | 140200425125253 |
7 | 12326505032235 |
oct | 1722436435541 |
9 | 416008435756 |
10 | 131340057441 |
11 | 5077904711a |
12 | 21555629829 |
13 | c5016c6528 |
14 | 64dd4565c5 |
15 | 363a817896 |
hex | 1e947a3b61 |
131340057441 has 4 divisors (see below), whose sum is σ = 175120076592. Its totient is φ = 87560038292.
The previous prime is 131340057439. The next prime is 131340057449. The reversal of 131340057441 is 144750043131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131340057441 - 21 = 131340057439 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131340057449) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21890009571 + ... + 21890009576.
It is an arithmetic number, because the mean of its divisors is an integer number (43780019148).
Almost surely, 2131340057441 is an apocalyptic number.
It is an amenable number.
131340057441 is a deficient number, since it is larger than the sum of its proper divisors (43780019151).
131340057441 is an equidigital number, since it uses as much as digits as its factorization.
131340057441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43780019150.
The product of its (nonzero) digits is 20160, while the sum is 33.
The spelling of 131340057441 in words is "one hundred thirty-one billion, three hundred forty million, fifty-seven thousand, four hundred forty-one".
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