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131341044313 = 433054442891
BaseRepresentation
bin111101001010010001…
…0010100101001011001
3110120000101100100120201
41322110202110221121
54122441301404223
6140200502222201
712326516312353
oct1722442245131
9416011310521
10131341044313
1150779660616
1221555a24961
13c50198078b
1464dd6320d3
15363a95eead
hex1e94894a59

131341044313 has 4 divisors (see below), whose sum is σ = 134395487248. Its totient is φ = 128286601380.

The previous prime is 131341044287. The next prime is 131341044353. The reversal of 131341044313 is 313440143131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131341044313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131341044353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1527221403 + ... + 1527221488.

It is an arithmetic number, because the mean of its divisors is an integer number (33598871812).

Almost surely, 2131341044313 is an apocalyptic number.

It is an amenable number.

131341044313 is a deficient number, since it is larger than the sum of its proper divisors (3054442935).

131341044313 is an equidigital number, since it uses as much as digits as its factorization.

131341044313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3054442934.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 131341044313 its reverse (313440143131), we get a palindrome (444781187444).

The spelling of 131341044313 in words is "one hundred thirty-one billion, three hundred forty-one million, forty-four thousand, three hundred thirteen".

Divisors: 1 43 3054442891 131341044313