13134104433 has 6 divisors (see below), whose sum is σ = 18971484194. Its totient is φ = 8756069616.

The previous prime is 13134104419. The next prime is 13134104497. The reversal of 13134104433 is 33440143131.

It can be written as a sum of positive squares in only one way, i.e., 12151093824 + 983010609 = 110232^2 + 31353^2 .

It is not a de Polignac number, because 13134104433 - 2³³ = 4544169841 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13134104397 and 13134104406.

It is not an unprimeable number, because it can be changed into a prime (13134104033) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 729672460 + ... + 729672477.

Almost surely, 2^13134104433 is an apocalyptic number.

It is an amenable number.

13134104433 is a deficient number, since it is larger than the sum of its proper divisors (5837379761).

13134104433 is a wasteful number, since it uses less digits than its factorization.

13134104433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1459344943 (or 1459344940 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 13134104433 its reverse (33440143131), we get a palindrome (46574247564).

The spelling of 13134104433 in words is "thirteen billion, one hundred thirty-four million, one hundred four thousand, four hundred thirty-three".