131341114310131 has 8 divisors (see below), whose sum is σ = 150822332222400. Its totient is φ = 113116749166440.

The previous prime is 131341114310129. The next prime is 131341114310213. The reversal of 131341114310131 is 131013411143131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131341114310131 - 2¹ = 131341114310129 is a prime.

It is a super-2 number, since 2×131341114310131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131341114310131.

It is not an unprimeable number, because it can be changed into a prime (131341114310101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 314213191921 + ... + 314213192338.

It is an arithmetic number, because the mean of its divisors is an integer number (18852791527800).

Almost surely, 2^{131341114310131} is an apocalyptic number.

131341114310131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

131341114310131 is a deficient number, since it is larger than the sum of its proper divisors (19481217912269).

131341114310131 is a wasteful number, since it uses less digits than its factorization.

131341114310131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 628426384289.

The product of its (nonzero) digits is 1296, while the sum is 28.

Adding to 131341114310131 its reverse (131013411143131), we get a palindrome (262354525453262).

The spelling of 131341114310131 in words is "one hundred thirty-one trillion, three hundred forty-one billion, one hundred fourteen million, three hundred ten thousand, one hundred thirty-one".