Search a number
-
+
1313412525033 = 3762543453573
BaseRepresentation
bin10011000111001101011…
…111001010101111101001
311122120010222101022122120
4103013031133022233221
5133004332101300113
62443212352341453
7163614405155040
oct23071537125751
94576128338576
101313412525033
11467019147824
1219266b244889
1396b14aa469b
14477d8a19557
15242716b1a23
hex131cd7cabe9

1313412525033 has 8 divisors (see below), whose sum is σ = 2001390514368. Its totient is φ = 750521442864.

The previous prime is 1313412525031. The next prime is 1313412525067. The reversal of 1313412525033 is 3305252143131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1313412525033 - 21 = 1313412525031 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313412524985 and 1313412525003.

It is not an unprimeable number, because it can be changed into a prime (1313412525031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31271726766 + ... + 31271726807.

It is an arithmetic number, because the mean of its divisors is an integer number (250173814296).

Almost surely, 21313412525033 is an apocalyptic number.

It is an amenable number.

1313412525033 is a deficient number, since it is larger than the sum of its proper divisors (687977989335).

1313412525033 is an equidigital number, since it uses as much as digits as its factorization.

1313412525033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62543453583.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 1313412525033 its reverse (3305252143131), we get a palindrome (4618664668164).

The spelling of 1313412525033 in words is "one trillion, three hundred thirteen billion, four hundred twelve million, five hundred twenty-five thousand, thirty-three".

Divisors: 1 3 7 21 62543453573 187630360719 437804175011 1313412525033