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131341657 = 702718691
BaseRepresentation
bin1111101010000…
…01110101011001
3100011010211212211
413311001311121
5232110413112
621011035121
73153246166
oct765016531
9304124784
10131341657
1168158a27
1237b9baa1
1321298375
141362d06d
15b7e60a7
hex7d41d59

131341657 has 4 divisors (see below), whose sum is σ = 131367376. Its totient is φ = 131315940.

The previous prime is 131341633. The next prime is 131341663. The reversal of 131341657 is 756143131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131341657 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131341057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2319 + ... + 16372.

It is an arithmetic number, because the mean of its divisors is an integer number (32841844).

Almost surely, 2131341657 is an apocalyptic number.

It is an amenable number.

131341657 is a deficient number, since it is larger than the sum of its proper divisors (25719).

131341657 is an equidigital number, since it uses as much as digits as its factorization.

131341657 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25718.

The product of its digits is 7560, while the sum is 31.

The square root of 131341657 is about 11460.4387786856. The cubic root of 131341657 is about 508.3164490913.

Adding to 131341657 its reverse (756143131), we get a palindrome (887484788).

The spelling of 131341657 in words is "one hundred thirty-one million, three hundred forty-one thousand, six hundred fifty-seven".

Divisors: 1 7027 18691 131341657