131342200000041 has 8 divisors (see below), whose sum is σ = 175223175431584. Its totient is φ = 87511345617600.

The previous prime is 131342200000027. The next prime is 131342200000051. The reversal of 131342200000041 is 140000002243131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2^k-131342200000041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131342199999963 and 131342200000017.

It is not an unprimeable number, because it can be changed into a prime (131342200000051) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12530256160 + ... + 12530266641.

It is an arithmetic number, because the mean of its divisors is an integer number (21902896928948).

Almost surely, 2^{131342200000041} is an apocalyptic number.

It is an amenable number.

131342200000041 is a deficient number, since it is larger than the sum of its proper divisors (43880975431543).

131342200000041 is a wasteful number, since it uses less digits than its factorization.

131342200000041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25060524551.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 131342200000041 its reverse (140000002243131), we get a palindrome (271342202243172).

The spelling of 131342200000041 in words is "one hundred thirty-one trillion, three hundred forty-two billion, two hundred million, forty-one", and thus it is an aban number.