131342212041441 has 4 divisors (see below), whose sum is σ = 175122949388592. Its totient is φ = 87561474694292.

The previous prime is 131342212041371. The next prime is 131342212041449. The reversal of 131342212041441 is 144140212243131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131342212041441 - 2¹⁷ = 131342211910369 is a prime.

It is not an unprimeable number, because it can be changed into a prime (131342212041449) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21890368673571 + ... + 21890368673576.

It is an arithmetic number, because the mean of its divisors is an integer number (43780737347148).

Almost surely, 2^{131342212041441} is an apocalyptic number.

It is an amenable number.

131342212041441 is a deficient number, since it is larger than the sum of its proper divisors (43780737347151).

131342212041441 is an equidigital number, since it uses as much as digits as its factorization.

131342212041441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43780737347150.

The product of its (nonzero) digits is 18432, while the sum is 33.

Adding to 131342212041441 its reverse (144140212243131), we get a palindrome (275482424284572).

The spelling of 131342212041441 in words is "one hundred thirty-one trillion, three hundred forty-two billion, two hundred twelve million, forty-one thousand, four hundred forty-one".