13134231221233 has 4 divisors (see below), whose sum is σ = 13135462527600. Its totient is φ = 13132999914868.

The previous prime is 13134231221149. The next prime is 13134231221249. The reversal of 13134231221233 is 33212213243131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13134231221233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13134231221195 and 13134231221204.

It is not an unprimeable number, because it can be changed into a prime (13134231521233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 615637183 + ... + 615658516.

It is an arithmetic number, because the mean of its divisors is an integer number (3283865631900).

Almost surely, 2^{13134231221233} is an apocalyptic number.

It is an amenable number.

13134231221233 is a deficient number, since it is larger than the sum of its proper divisors (1231306367).

13134231221233 is a wasteful number, since it uses less digits than its factorization.

13134231221233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1231306366.

The product of its digits is 15552, while the sum is 31.

Adding to 13134231221233 its reverse (33212213243131), we get a palindrome (46346444464364).

The spelling of 13134231221233 in words is "thirteen trillion, one hundred thirty-four billion, two hundred thirty-one million, two hundred twenty-one thousand, two hundred thirty-three".