1313425650433 has 8 divisors (see below), whose sum is σ = 1434380342976. Its totient is φ = 1195316950800.

The previous prime is 1313425650419. The next prime is 1313425650437. The reversal of 1313425650433 is 3340565243131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1313425650433 is a prime.

It is a super-2 number, since 2×1313425650433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313425650437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 711497263 + ... + 711499108.

It is an arithmetic number, because the mean of its divisors is an integer number (179297542872).

Almost surely, 2^{1313425650433} is an apocalyptic number.

1313425650433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1313425650433 is a deficient number, since it is larger than the sum of its proper divisors (120954692543).

1313425650433 is a wasteful number, since it uses less digits than its factorization.

1313425650433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1422996455.

The product of its (nonzero) digits is 388800, while the sum is 40.

The spelling of 1313425650433 in words is "one trillion, three hundred thirteen billion, four hundred twenty-five million, six hundred fifty thousand, four hundred thirty-three".