Base | Representation |
---|---|
bin | 11101110111010010111000… |
… | …110110111111000001001011 |
3 | 122020001021202112021212020022 |
4 | 131313102320312333001023 |
5 | 114203411334020131243 |
6 | 1143202122252051055 |
7 | 36444142653516230 |
oct | 3567227066770113 |
9 | 566037675255208 |
10 | 131343201333323 |
11 | 38939380051581 |
12 | 12893238463a8b |
13 | 58397c2a49545 |
14 | 246108b169787 |
15 | 102b811068b68 |
hex | 7774b8dbf04b |
131343201333323 has 4 divisors (see below), whose sum is σ = 150106515809520. Its totient is φ = 112579886857128.
The previous prime is 131343201333241. The next prime is 131343201333341. The reversal of 131343201333323 is 323333102343131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131343201333323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131043201333323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9381657238088 + ... + 9381657238101.
It is an arithmetic number, because the mean of its divisors is an integer number (37526628952380).
Almost surely, 2131343201333323 is an apocalyptic number.
131343201333323 is a deficient number, since it is larger than the sum of its proper divisors (18763314476197).
131343201333323 is an equidigital number, since it uses as much as digits as its factorization.
131343201333323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18763314476196.
The product of its (nonzero) digits is 104976, while the sum is 35.
Adding to 131343201333323 its reverse (323333102343131), we get a palindrome (454676303676454).
The spelling of 131343201333323 in words is "one hundred thirty-one trillion, three hundred forty-three billion, two hundred one million, three hundred thirty-three thousand, three hundred twenty-three".
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